Flag Electric Current> Hi Friends, Can anyone please explain me ...
question mark

Hi Friends, Can anyone please explain me in detail this objective question.The Escape velocity for a planet is V. A Tunnel is dug along a diameter of the planet and a small body is dropped into it at the surface. When the body reaches the centre of the planet,it's speed will be (in terms of V) -

Radhika Batra , 12 Years ago
Grade 11
anser 1 Answers
Askiitians Tutor Team

To tackle this question, we need to delve into the concepts of escape velocity and gravitational potential energy. The escape velocity for a planet is the minimum speed needed for an object to break free from the planet's gravitational pull without any additional propulsion. For our purposes, let's denote this escape velocity as V.

Understanding Escape Velocity

Escape velocity is derived from the balance between kinetic energy and gravitational potential energy. The formula for escape velocity (V) is given by:

  • V = √(2GM/R)

Here, G is the gravitational constant, M is the mass of the planet, and R is its radius. This means that the escape velocity depends on the mass and size of the planet.

What Happens When the Body is Dropped?

Now, let’s consider the scenario where a small body is dropped into a tunnel that runs through the diameter of the planet. Initially, when the body is at the surface, it has gravitational potential energy due to its height above the center of the planet. As it falls towards the center, this potential energy is converted into kinetic energy.

Energy Conservation Principle

According to the conservation of mechanical energy, the total energy (potential + kinetic) remains constant if we ignore air resistance and other dissipative forces. At the surface, the body has maximum potential energy and zero kinetic energy. As it falls, potential energy decreases while kinetic energy increases.

Speed at the Center of the Planet

When the body reaches the center of the planet, all the potential energy will have been converted into kinetic energy. The gravitational potential energy (U) at the surface can be expressed as:

  • U = -GMm/R

At the center, the potential energy is at its minimum (most negative), and the kinetic energy (K) can be expressed as:

  • K = (1/2)mv²

Setting the initial potential energy equal to the kinetic energy at the center gives us:

  • -GMm/R = (1/2)mv²

By simplifying this equation (noting that mass m cancels out), we can solve for the speed v at the center:

  • v² = 2GM/R
  • v = √(2GM/R)

Notice that this expression for v is identical to the formula for escape velocity (V). Therefore, we can conclude that:

  • The speed of the body when it reaches the center of the planet is equal to the escape velocity, V.

Final Thoughts

In summary, when the small body is dropped into the tunnel and reaches the center of the planet, its speed will be V, the escape velocity of the planet. This fascinating interplay of gravitational forces and energy conservation illustrates the beauty of physics in understanding motion and energy transformations.

ApprovedApproved
Last Activity: 9 Months ago
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments