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Grade: 12th
`        Hey man throw about maximum horizontal distance of 80 metre calculate the maximum height reached`
2 years ago

## Answers : (1)

Arun
23742 Points
```							Dear sayyad We know that R = u2 * Sin 2θ / g.As, the range is maximum, so, θ = 450So, 80 = u2 /g.Now, H = height reached by ball =  u2 Sin2θ / 2g.Putting value of θ = 450 , u2 / g = 80, we getH = 80/4  = 20m RegardsArun (askIITians forum expert)
```
2 years ago
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