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The work done to lift the hanging part of the cable up to the surface is MgL/2n²Given-Mass of uniform cable = MLength of cable = LLength of cable hanging below the edge of the surface is = 1/n th partMass of the hanging part = M/nCenter of mass of h = L/2nSo work done should be-W = mgh = (M/n) g (L/2n)W = MgL/2n²
Dear student There is short cut.Work done against gravity = mgh = m/n g l/2n = mgl /2n^2Good Luck Cheers
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