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hello, I have a question regarding kinematics.A block of mass 5 Kg is moving on a smooth surface with 20 m/s and ends at a quarter verticle circular loop of radius 2 m. What is the time taken by the block to complete the circular track?

Abhijeet Peshkar , 8 Years ago
Grade 12th pass
anser 1 Answers
Vikas TU

Last Activity: 8 Years ago

taking U = 0 as refernce from smooth surface (horizontal)
conserve K.E and P.E for block.
Therefore,
0.5*5*400 = 5*g*2 + 0.5*5*v^2
v = root(360)
v = 18.973 m/s
 
From 2nd law of eqn.,
2 = 20*t – 0.5g*t^2
1 = 10t –  2.5t^2
or
2.5t^2 – 10t + 1 = 0
solve the quaratic and get the value if t.

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