hello, I have a question regarding kinematics.A block of mass 5 Kg is moving on a smooth surface with 20 m/s and ends at a quarter verticle circular loop of radius 2 m. What is the time taken by the block to complete the circular track?
Abhijeet Peshkar , 8 Years ago
Grade 12th pass
1 Answers
Vikas TU
Last Activity: 8 Years ago
taking U = 0 as refernce from smooth surface (horizontal)
conserve K.E and P.E for block.
Therefore,
0.5*5*400 = 5*g*2 + 0.5*5*v^2
v = root(360)
v = 18.973 m/s
From 2nd law of eqn.,
2 = 20*t – 0.5g*t^2
1 = 10t – 2.5t^2
or
2.5t^2 – 10t + 1 = 0
solve the quaratic and get the value if t.
Provide a better Answer & Earn Cool Goodies
Enter text here...
LIVE ONLINE CLASSES
Prepraring for the competition made easy just by live online class.
Full Live Access
Study Material
Live Doubts Solving
Daily Class Assignments
Ask a Doubt
Get your questions answered by the expert for free