Grade 11Mechanics

he linear momentum p of a particle is given as a function of time t as p = at ^2 +Bt + c the dimensioin of constant B are

Prince

8 Years agoGrade 11

2 Answers

Shailendra Kumar Sharma

8 Years ago

P=At2 + Bt +CDimension of P = mvi.e. MLT^(-1) And now dimension of Bt and C must be same as PSo dimension of C is MLT^(-1) Dimension of B will be MLT^(-2)

jahska

7 Years ago

Given,

P=At^2+Bt+C, where A,B and C are constants.

Also,linear momentum(P)=MLT^-1

So, MLT^-1=At^2+Bt+C, C=MLT^-2 [since it is a constant]

therefore,MLT^-1=Bt

= MLT^-1/T^1=MLT^-2, Hope it was helpful :)

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he linear momentum p of a particle is given as a function of time t as p = at ^2 +Bt + c the dimensioin of constant B are

Prince

2 Answers

Shailendra Kumar Sharma

jahska

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