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Grade: 11

                        

he linear momentum p of a particle is given as a function of time t as p = at ^2 +Bt + c the dimensioin of constant B are

3 years ago

Answers : (2)

Shailendra Kumar Sharma
188 Points
							P=At2 + Bt +CDimension of P = mvi.e. MLT^(-1) And now dimension of Bt and C must be same as PSo dimension of C is MLT^(-1) Dimension of B will be MLT^(-2)
						
3 years ago
jahska
13 Points
							
Given,
P=At^2+Bt+C, where A,B and C are constants.
Also,linear momentum(P)=MLT^-1
So, MLT^-1=At^2+Bt+C, C=MLT^-2 [since it is a constant]
therefore,MLT^-1=Bt
                           = MLT^-1/T^1=MLT^-2, Hope it was helpful  :)
one year ago
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