he linear momentum p of a particle is given as a function of time t as p = at ^2 +Bt + c the dimensioin of constant B are

Question

Shailendra Kumar Sharma · Answer

P=At2 + Bt +CDimension of P = mvi.e. MLT^(-1) And now dimension of Bt and C must be same as PSo dimension of C is MLT^(-1) Dimension of B will be MLT^(-2)

jahska · Answer

Given, P=At^2+Bt+C, where A,B and C are constants. Also,linear momentum(P)=MLT^-1 So, MLT^-1=At^2+Bt+C, C=MLT^-2 [since it is a constant] therefore,MLT^-1=Bt = MLT^-1/T^1=MLT^-2, Hope it was helpful :)

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he linear momentum p of a particle is given as a function of time t as p = at ^2 +Bt + c the dimensioin of constant B are

he linear momentum p of a particle is given as a function of time t as p = at ^2 +Bt + c the dimensioin of constant B are

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