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```
he linear momentum p of a particle is given as a function of time t as p = at ^2 +Bt + c the dimensioin of constant B are

```
3 years ago

Shailendra Kumar Sharma
188 Points
```							P=At2 + Bt +CDimension of P = mvi.e. MLT^(-1) And now dimension of Bt and C must be same as PSo dimension of C is MLT^(-1) Dimension of B will be MLT^(-2)
```
3 years ago
jahska
13 Points
```							Given,P=At^2+Bt+C, where A,B and C are constants.Also,linear momentum(P)=MLT^-1So, MLT^-1=At^2+Bt+C, C=MLT^-2 [since it is a constant]therefore,MLT^-1=Bt                           = MLT^-1/T^1=MLT^-2, Hope it was helpful  :)
```
one year ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions