Grade 12th passMechanics

Gshell is fired from the ground at an angle theta with the horizontal with a velocity v its highest point it break into two equal fragments if one fragment come back through it initial line of the motion with the same speed then the speed of the second figment will be?

S

6 Years agoGrade 12th pass

1 Answer

Arun

6 Years ago

Dear student

Let ‘2m’ be the mass of the cannon which is projected with velocity ‘v’ at an angle ‘θ’ with the horizontal. The horizontal component of the velocity of the cannon is, vx = v cosθ. This component remains constant.

At the maximum height, the cannon has only this component as the vertical component is momentarily zero.

So, momentum before exploding = 2mv cosθ

After exploding, one of the masses retraces the path of the cannon backwards. This is possible on if the part has velocity ‘-v cosθ’.

Therefore, momentum after explosion = -mv cosθ + mu

So, by conservation of momentum,

2mv cosθ = -mv cosθ + mu

= > u = (3v cosθ) m/s

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Gshell is fired from the ground at an angle theta with the horizontal with a velocity v its highest point it break into two equal fragments if one fragment come back through it initial line of the motion with the same speed then the speed of the second figment will be?

S

1 Answer

Arun

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