0

Guest

Courses New

Gravitational due to an infinitely long thin rod of linear density P from a point of mass M and perpendicular distance from rod to point is L

Gravitational due to an infinitely long thin rod of linear density P from a point of mass M and perpendicular distance from rod to point is L

Grade:11

1 Answers

Sai Ram Charan
31 Points
6 years ago
Data provided is inconsistent; anyway, we have the following data-
Length of rod=1/0 , magnitude of point mass= ‘m’​, distance of seperation= l
Therefore, from Newton’s Law of universal Gravitation, we have F=
 
-G{m_{1}m_{2} \over {\vert \mathbf {r} _{12}\vert }^{2}}\,\mathbf {\hat {r}} _{12}}(in vector calculuss form)
Clearly, the force is
 
 \frac{G P \frac{1}{0} m}{l^{2}}

Think You Can Provide A Better Answer ?

Other Related Questions on Mechanics

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More