Grade 11Mechanics

Given that p+q+r=0. two of them are equal in magnitude. the magnitude of third vector is √2 times that of the other two. which are the angles between these two vectors?
90, 135, 135
45, 45, 135
30, 60, 90
45, 90, 135
plz answer fast..

SS

8 Years agoGrade 11

1 Answer

Mohsin syed

7 Years ago

Given:P+Q+R=0

SO,

P+Q=-R

Given P=Q

P²+p²+2p²Cos∆=-q²

2p²+2p²cos∆=(p√2)²

2p²Cos∆=2p²-2p²

Cos∆=0

∆= 90 degree= angle btw p & q

Now btw p and R

P² +(p √2)²+2(p)(p√2)cos ∆= -q²

P²+ 2p² +2p²√2cos∆=p²

2p²√2cos∆=-2p²

Cos∆= -2p²/2p²√2

Cos∆ =-1/√2

∆= 135 degree

Hence angles are 90,135 q35

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Given that p+q+r=0. two of them are equal in magnitude. the magnitude of third vector is √2 times that of the other two. which are the angles between these two vectors?90, 135, 13545, 45, 13530, 60, 9045, 90, 135plz answer fast..

SS

1 Answer

Mohsin syed

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Given that p+q+r=0. two of them are equal in magnitude. the magnitude of third vector is √2 times that of the other two. which are the angles between these two vectors?
90, 135, 135
45, 45, 135
30, 60, 90
45, 90, 135
plz answer fast..

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31
41