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Given mA=30 KG,mB=10 KG,mC=20 KG.Between A and B friction coefficent 0.3, between B and C friction coefficient 0.2 and between C and ground is 0.1 . The least horizontal force F to start the motion of any part of the system of three blocks as shown in the figure is(g=10 m/s2) :


2 years ago

Arun
24741 Points
							Dear Monali Frictional force between a and B is F1 = 0.3 * 30 * 10 = 90 N                                       B and C is F2 = 0.2 * 40 * 10 = 80N Any frictional force between ground is = 0.1 * 60 * 10 = 60 N So if you apply 60 N force then whole block will starts moving with respectto ground. Hence correct answer isSo if you apply 60 N force then whole block will starts moving with respectto ground. Hence correct answer isSo if you apply 60 N force then whole block will starts moving with respectto ground. Hence correct answer isSo if you apply 60 N force block willstarts moving with respect to ground

2 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions