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Grade: 11

                        

Given a vector A = 2i + 3j and a vector B = i + j. The component of the vector A along B is (a) 1/(2)½ (i + j) (b) 3/(2)½ (i + j) (c) 5/(2)½ (i + j) (d) 7/(2)½ (i + j)

4 years ago

Answers : (6)

Vikas TU
12276 Points
							
The component of the vector A along B geometrically is:
Bcos(theta) = (A.B/|B|).(Bcap)
                   =5/(2)½   (i + j)
  1.  option is correct.
4 years ago
Pushkar Ranjan
24 Points
							
A along B is given as” A cosθ = A.B/|B|”
which formulates to give 2+3 √2 = 5/ √2
the option  (c.) is correct
 
2 years ago
meet kumar
15 Points
							
As we know 
ABcosø=A.B
From this eq we get
ACosø=A.B/|B|
by putting values from given data
A Cosø=5/root2
Soo C is the right option
2 years ago
M
13 Points
							
2square+3square whole root=5
1square+1square whole root=root 2
then multiply 
both you could get needed answer 
that is 5root2
 
one year ago
Aahira
13 Points
							
The component of A along vector B=) A. B) where B^=B/b where b is the magnitude of vector B ... 
Now do A. B 
Thn find B^ wch is rdq soln
one year ago
Rishi Sharma
askIITians Faculty
614 Points
							Hello students,
The problemis of vector and asked the component of A along B.
We know that,
the component of the vector A along B geometrically is :=(A.B).(Bcap)
=(A.B).(B/|B|)
=((2i +3j) . (i + j)) . ((i+j)/(2)½)
=(2+3) . ((i+j)/(2)½)
=5/(2)½ (i + j)
I hope this solution would solve your all doubts.
Thank You

4 months ago
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