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```
Given a vector A = 2i + 3j and a vector B = i + j. The component of the vector A along B is (a) 1/(2)½ (i + j) (b) 3/(2)½ (i + j) (c) 5/(2)½ (i + j) (d) 7/(2)½ (i + j)

```
4 years ago

```							The component of the vector A along B geometrically is:Bcos(theta) = (A.B/|B|).(Bcap)                   =5/(2)½   (i + j)	 option is correct.
```
4 years ago
```							A along B is given as” A cosθ = A.B/|B|”which formulates to give 2+3 / √2 = 5/ √2the option  (c.) is correct
```
2 years ago
```							As we know ABcosø=A.BFrom this eq we getACosø=A.B/|B|by putting values from given dataA Cosø=5/root2Soo C is the right option
```
2 years ago
```							2square+3square whole root=51square+1square whole root=root 2then multiply both you could get needed answer that is 5root2
```
one year ago
```							The component of A along vector B=) A. B) where B^=B/b where b is the magnitude of vector B ... Now do A. B Thn find B^ wch is rdq soln
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one year ago
```							Hello students,The problemis of vector and asked the component of A along B.We know that,the component of the vector A along B geometrically is :=(A.B).(Bcap)=(A.B).(B/|B|)=((2i +3j) . (i + j)) . ((i+j)/(2)½)=(2+3) . ((i+j)/(2)½)=5/(2)½ (i + j)I hope this solution would solve your all doubts.Thank You
```
4 months ago
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