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Given a right angled isosceles triangular plate of mass m and base l. The plate is attached to an axis at an apex angle of 90 degrees. The apex lies at origin and the base is parallel to x-axis. The moment of inertia about x-axis is:1) ml^2/242)ml^2/123)ml^2/84)ml^2/6
let axis of rotation pass through hypotenuse. considering rotation about hypotenuse u will see ki triange ke do partts se ek square ban jayege and hypotenuse square ka diagonal hoga. we know square ke daigomal se pass axis ka mi=ml^2/6if mass of sq is m now triangle ka mass sq ke mass ka half hoga to mi abt hypotenuse =ml^2/12 now apply perpendicular axis thm mi about base as well as perp is ml^2/24
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