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From the top of a tower, a stone is thrown vertically up which reaches the ground in time t1.A second stone thrown vertically down with the same speed reaches the ground in a time t2. A thrid stone released from rest from the same location, reaches the ground in a time t3. Then,t1+t2/2. t3=(t1*t2)½ 1/t3=1/t2-1/t1. t32=t12-t22answer is : B. how?

kushi , 9 Years ago
Grade 12
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