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From the top of a building a ball was projected horizontally the ball strikes the ground after 5 seconds at an angle of 60 degree with horizontal calculate the speed with which the ball was projected.Explain in a simple way. Thanks ๐Ÿ™๐Ÿ™

From the top of a building a ball was projected horizontally the ball strikes the ground after 5 seconds at an angle of 60 degree with horizontal calculate the speed with which the ball was projected.Explain in a simple way. Thanks ๐Ÿ™๐Ÿ™

Grade:9

2 Answers

Vamshi
15 Points
4 years ago
Three particles each of mass 2kg are at corners of an equilateral triangle of side โˆš3m.if one of the particle is removed,the shift in cm is
Khimraj
3007 Points
4 years ago
After 5 seconds , vertical component of velocity = (1/2)gt2ย = (1/2)ร—9.8ร—5ร—5 = 122.5 m/s
ย 
if u is projection velocity along horizontal direction at top of building and resultant velocity makes angle 60ยฐ with horizontal,
ยฝgt2/u = tan60
u = 70.73 m/s

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