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Grade: 9
        
From the top of a building a ball was projected horizontally the ball strikes the ground after 5 seconds at an angle of 60 degree with horizontal calculate the speed with which the ball was projected.Explain in a simple way. Thanks 🙏🙏
4 months ago

Answers : (2)

Vamshi
15 Points
							
Three particles each of mass 2kg are at corners of an equilateral triangle of side √3m.if one of the particle is removed,the shift in cm is
4 months ago
Khimraj
3008 Points
							
After 5 seconds , vertical component of velocity = (1/2)gt2 = (1/2)×9.8×5×5 = 122.5 m/s
 
if u is projection velocity along horizontal direction at top of building and resultant velocity makes angle 60° with horizontal,
½gt2/u = tan60
u = 70.73 m/s
4 months ago
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