badge image

Enroll For Free Now & Improve Your Performance.

×
User Icon
User Icon
User Icon
User Icon
User Icon

Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11

                        

From a solid sphere of radius R a solid spherical mass of radius R/2 is cut out from near its surface. Find the shift in the position of C.O.M.

4 years ago

Answers : (1)

Shaswata Biswas
132 Points
							
Let the mass of bigger sphere be M with rafius R. Then the mass of smaller sphere with radius R/2 is M/4.
Let the centre of the big sphere which is its centre of mass be the origin O. Then the centre of mass of the small sphere is at a distance R/2 from O.
When the small sphere is cut out, let the C.M. of the remaining portion shifts to P. Mass of remaining portion = 3M/4.
From conservation of centre of mass : 
C.M. of remaining portion = C.M. of big sphere + C.M. of the small sphere.
=> \frac{3M}{4}*(-OP) = M*OO + \frac{M}{4}*\frac{R}{2}
=> OP = -\frac{R}{6}
So, the centre of mass of the remaining portion shifts to \frac{R}{6} from tge centre of the circle.
THANKS
4 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details