Create your Smart Home App in the Free Webinar on Home Automation. Register Now
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Free webinar on App Development Learn to create your own Smart Home App
16th Jan @ 5:00PM for Grade 1 to 10
Sit and relax as our customer representative will contact you within 1 business day
From a solid sphere of radius R a solid spherical mass of radius R/2 is cut out from near its surface. Find the shift in the position of C.O.M.
Let the mass of bigger sphere be M with rafius R. Then the mass of smaller sphere with radius R/2 is M/4.Let the centre of the big sphere which is its centre of mass be the origin O. Then the centre of mass of the small sphere is at a distance R/2 from O.When the small sphere is cut out, let the C.M. of the remaining portion shifts to P. Mass of remaining portion = 3M/4.From conservation of centre of mass : C.M. of remaining portion = C.M. of big sphere + C.M. of the small sphere.=> => OP = So, the centre of mass of the remaining portion shifts to from tge centre of the circle.THANKS
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -