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From a highest point "O " two bodies are thrown opposites direction horizontally with velocities 3m/s and 4 m/s .find the distance between them after some time when their velocity vector become mutually perpendicular
v1=3i – gtjv2= – 4i – gtj v1.v2=0 for 90 deg – 12+g^2t^2=0gt=root12t=root(12) /10distance = 7 *root(12)/10
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