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from a circular rotating frame about its center axis with constant angular velocity of 70 rpm of radius 12 inch, a particle of mass 0.01lb is projected making an angle of 60 deg with horizontal plane with a velocity of 200 inch/sec. how to find the path of the projectile.

abhisek , 9 Years ago
Grade 12th pass
anser 1 Answers
Askiitians Tutor Team

To determine the path of a projectile launched from a circular rotating frame, we need to consider both the motion of the particle and the effects of the rotation. The key here is to break down the problem into manageable components, taking into account the initial conditions and the forces acting on the particle.

Understanding the Setup

We have a particle with a mass of 0.01 lb projected at an angle of 60 degrees with an initial velocity of 200 inches per second from a rotating frame. The frame rotates at a constant angular velocity of 70 revolutions per minute (rpm) and has a radius of 12 inches. To analyze the projectile's motion, we must convert the angular velocity to a more usable unit and then apply the principles of projectile motion.

Convert Angular Velocity

First, let's convert the angular velocity from rpm to radians per second:

  • 1 revolution = 2π radians
  • 70 rpm = 70 revolutions/minute × (2π radians/revolution) × (1 minute/60 seconds) = (70 × 2π)/60 radians/second
  • Calculating this gives approximately 7.33 radians/second.

Initial Velocity Components

Next, we need to resolve the initial velocity into horizontal and vertical components. The angle of projection is 60 degrees:

  • Horizontal component (Vx) = V * cos(θ) = 200 * cos(60°) = 200 * 0.5 = 100 inches/second.
  • Vertical component (Vy) = V * sin(θ) = 200 * sin(60°) = 200 * (√3/2) ≈ 173.21 inches/second.

Inertial and Rotational Effects

Since the frame is rotating, the particle will experience a centrifugal force in addition to gravitational force. The centrifugal acceleration (a_c) can be calculated using the formula:

  • a_c = ω² * r, where ω is the angular velocity in radians/second and r is the radius.
  • Substituting the values: a_c = (7.33)² * 12 ≈ 646.63 inches/second².

Equations of Motion

The equations of motion for the projectile can be described as follows:

  • Horizontal motion: x(t) = x₀ + Vx * t + 0.5 * a_c * t², where x₀ is the initial horizontal position.
  • Vertical motion: y(t) = y₀ + Vy * t - 0.5 * g * t², where g is the acceleration due to gravity (approximately 386 inches/second²).

Path of the Projectile

To find the path, we can eliminate time (t) from these equations. By expressing time from the horizontal motion equation and substituting it into the vertical motion equation, we can derive a relationship between x and y. This will give us the trajectory of the projectile in the rotating frame.

Example Calculation

Assuming the particle is projected from the origin (0,0), we can set up the equations:

  • From horizontal motion: t = (x - 0) / (100 + 0.5 * 646.63 * t).
  • Substituting this into the vertical motion equation will yield a complex equation, but it can be solved numerically or graphically to find the path.

Final Thoughts

In summary, the path of the projectile launched from a rotating frame can be determined by analyzing the initial velocity components, the effects of centrifugal force, and applying the equations of motion. The resulting trajectory will be influenced by both the initial launch conditions and the rotation of the frame. For practical applications, numerical methods or simulations may be employed to visualize the path accurately.

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