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Four particles A,B,C and D of equal mass move with equal speed v along the diagonals of a square in a horizontal plane. After the collision, A comes to rest while B and C retrace their paths with same speeds. Then the particle D will(a)continue to move along the same line with speed v(b)retrace its path with speed 2v(c)come to rest(d)move with speed v*root2 along a line parallel to CD
Appply momentum conservation in x and y direction for 4 masses simulatneously.Therefore, in x direcitonPi = Pf2mvi – 2mvi = 0 + -mvi – mvi + mvdmvd = 2mvivd = 2viwhere i is the i cap direcn.not conserve the same for y dirction.
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