Grade 11Mechanics

Four forces acting on apoint .The first force is 200 N acting due north ,the second is 100 N acting due south ,third force is 500 N acting East and the fourth is 300 N acting west . What is the magnitude and direction of the resultant force?

Souvik Garai

6 Years agoGrade 11

2 Answers

Vikas TU

6 Years ago

Dear student

Effective force along north direction=200j-100j=100j (j is unit vector along y axis)

Effective force along east direction=500i-300i=200i(i is the unit vector along x axis)

Now the net force=100j+200i

Magnitude of force = 223.606 N
Direction of resultant force = tan^-1(1/2)

Kamble nagnath baburav

4 Years ago

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Four forces acting on apoint .The first force is 200 N acting due north ,the second is 100 N acting due south ,third force is 500 N acting East and the fourth is 300 N acting west . What is the magnitude and direction of the resultant force?

Souvik Garai

2 Answers

Vikas TU

Kamble nagnath baburav

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