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`          force F=-k(yi+xj) where k is a positive constant acts on a particle moving in the xy plane. Starting from the origin the particle is taken along the positive x axis to the point (a,0) and then parallel to y axis to the point (a,a). Find the total work done by the force F in the particle.7 years ago`
one year ago

Arun
24739 Points
```							 F = -k(xi+yj)W = F.dr              (dot product of force & displacement)displacement vector(dr) is of line joining initial & final position vectors...W = -k(xi+yj).(dxi+dyj)W = -2k[xy] lim (0,0) to (a,a)W = -2ka2this is the amount of work
```
one year ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions