Grade 12Mechanics
for frictionless floor,find acceleration of point p
for frictionless floor,find acceleration of point p
1 Answer
Vikas TU
If force =5N
Tension in string = 5N
a = 3*5 /5 = 15/5 = 3m/s^2
a'= 2*5 /5 = 10/5 = 2m/s^2
P = 3a + 2a'
= 9 + 4 = 13 m/sec^2
Tension in string = 5N
a = 3*5 /5 = 15/5 = 3m/s^2
a'= 2*5 /5 = 10/5 = 2m/s^2
P = 3a + 2a'
= 9 + 4 = 13 m/sec^2
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