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Grade: 12
        
for frictionless floor,find acceleration of point p
6 months ago

Answers : (1)

Vikas TU
9484 Points
							
If force =5N 
Tension in string = 5N 
a = 3*5 /5 = 15/5 = 3m/s^2 
a'= 2*5 /5 = 10/5 = 2m/s^2
P = 3a + 2a' 
= 9 + 4 = 13 m/sec^2 
 
one month ago
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