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Find the time of flight of a projectile thrown horizontally with speed 10m/sec from a long inclined plane which makes an angle of 45 degree from the horizontal.

Purva , 6 Years ago
Grade 11
anser 2 Answers
Arun

Last Activity: 6 Years ago

Dear student
 
We know as
Time of flight = 2u sin theta/g
 
 = 2 * 10 * sin45°/10 = 2 * 1/sqrt(2)
 
 = sqrt(2) = 1.414 sec

Akshat Gupta

Last Activity: 6 Years ago

Vertical Component of velocity =usin∂  m/s
Acceleration due to gravity=g=10m/s^2
Time of Flight = 2usin∂/g
                          = 2×10×sin45°/10
                          = 20×1/√2×1/10
                          = 2/√2=√2=1.414s

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