Mercy Akintimehin
Last Activity: 3 Years ago
Using the formula: Moment of inertia, I=mk^2 +mh^2(Where k is the radius of gyration)Hence, by collecting like termsK=√(I-mh^2÷m)K=√(4.2×10^-2 - 0.05×0.1^2 ÷0.05)K=2.88mPeriod of oscillation, T=2π√(I/mghT=2×22/7√(4.2×10^-2/0.05×9.8×0.1)T=5.8secsThanks 😊