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Grade 11Mechanics

Find the minimum value of force F and the angle at which the force is applied

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8 Years agoGrade 11
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ApprovedApproved Tutor Answer1 Year ago

To determine the minimum value of force \( F \) and the angle at which it should be applied, we need to consider the context of the problem. Typically, this involves analyzing a situation where a force is applied to move an object against friction or to achieve a specific motion. Let's break this down step by step.

Understanding the Problem

Imagine you have an object resting on a horizontal surface, and you want to push it with a force \( F \) at an angle \( \theta \) to the horizontal. The goal is to find the minimum force required to overcome static friction and initiate movement.

Key Concepts

  • Force Components: When a force is applied at an angle, it can be broken down into two components: the horizontal component \( F_x = F \cos(\theta) \) and the vertical component \( F_y = F \sin(\theta) \).
  • Normal Force: The normal force \( N \) acting on the object is affected by the vertical component of the applied force. It can be expressed as \( N = mg - F_y \), where \( m \) is the mass of the object and \( g \) is the acceleration due to gravity.
  • Frictional Force: The frictional force \( f \) opposing the motion is given by \( f = \mu N \), where \( \mu \) is the coefficient of static friction.

Setting Up the Equations

To find the minimum force \( F \), we need to ensure that the horizontal component of the applied force is equal to the frictional force at the point of motion initiation. This gives us the equation:

Frictional Force: \( f = \mu N = \mu (mg - F \sin(\theta)) \)

Horizontal Force Balance: \( F \cos(\theta) = f \)

Combining the Equations

Substituting the expression for the frictional force into the horizontal force balance equation, we get:

Equation: \( F \cos(\theta) = \mu (mg - F \sin(\theta)) \)

Rearranging this equation allows us to isolate \( F \):

Rearranged: \( F \cos(\theta) + \mu F \sin(\theta) = \mu mg \)

This can be factored as:

Factored Form: \( F (\cos(\theta) + \mu \sin(\theta)) = \mu mg \)

From this, we can solve for \( F \):

Minimum Force: \( F = \frac{\mu mg}{\cos(\theta) + \mu \sin(\theta)} \)

Finding the Optimal Angle

To minimize \( F \), we need to analyze the expression \( \cos(\theta) + \mu \sin(\theta) \). This can be done using calculus or by recognizing that it resembles the form of a trigonometric identity.

By differentiating the expression or using trigonometric identities, we can find the angle \( \theta \) that minimizes \( F \). The optimal angle can be derived as:

Optimal Angle: \( \tan(\theta) = \frac{1}{\mu} \)

This means that the angle \( \theta \) at which the force should be applied to achieve the minimum value of \( F \) is given by:

Angle: \( \theta = \tan^{-1}\left(\frac{1}{\mu}\right) \)

Summary of Results

In summary, the minimum force \( F \) required to move an object at rest, when applied at an angle \( \theta \), can be calculated using the derived formula. The angle at which this minimum force occurs is determined by the coefficient of static friction. This approach not only provides a clear method for solving the problem but also illustrates the interplay between force, angle, and friction in practical scenarios.