MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 10
        
Find the mass M of the hanging block which will prevent the smaller block from slipping over the triangular block. All the surfaces are frictionless and the string and pulley are light.
one year ago

Answers : (1)

Satyam Agarwal
36 Points
							
Smaller block will slip due to the weight of the body parallel to the plane ,i.e.mgsin (theta).
 To prevent slipping we require an pseudo force ..
Pseudo force will arise due to the motion of the inclined plane . Let the acceleration of the inclined plane be a.
 Pseudo force( ma) will act horizontally leftward on small block. Component of this force will balance the component of weight.
Thus, 
macos(theta) = mgsin (theta) 
 a = g tan theta
Now we know the acceleration of the inclined plane. This acceleration is provided by the tension force.
Thus tension force = mass of inclined plane * acceleration = M' gtan theta
Now , this tension force will be balanced by the hanging block.
Thus T = Mg
M'gtan theta = Mg
M = M'tan theta.
 
Let me know  if the answer is incorrect.
Hope u get the concept now.
Thanks.
one year ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details