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find the average velocity of a particle released from rest from a hieght of 125 m over time interval till it sirkes the ground
find the average velocity of a particle released from rest from a hieght of 125 m over time interval till it sirkes the ground

```
2 years ago

Susmita
425 Points
```							At height h=125m,velocity u=0.h=ut+gt2/2=gt2/2=5t2 taking g=10m/s2or,t=root(h/5)=root(125/5)=5sSo average speed=(distance covered)/time elasped=125/5=25 m/sHope this helps.
```
2 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions