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Grade: 12 

                        
find the average velocity of a particle released from rest from a hieght of 125 m over time interval till it sirkes the ground
2 years ago

Answers : (1)

Susmita
425 Points 
							
At height h=125m,velocity u=0.
h=ut+gt2/2=gt2/2=5t2 taking g=10m/s2
or,t=root(h/5)=root(125/5)=5s
So average speed=(distance covered)/time elasped=125/5=25 m/s
Hope this helps.
 
 
2 years ago
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