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Grade: 12th pass

                        

Find average acceleration over 10 seconds.. ........... Graph is shown in attachment

2 years ago

Answers : (1)

Susmita
425 Points
							
For 0 to 5 s,it is a straight line passing through origin with slope 10/5=2.
The equation of straight line is a=2t.
Or,dv/dt=2t
Or,dv=2tdt
Integrate dv from 0 to v and dt from t 0 to 5,you will get
v=25.
For the next 5s,initial velocity u=5m/s and acceleration a=10m/s2.So final velocity
v=u+at=25+10×5=75 m/s
So average acceleration in 10 s is
(75-0)/10=7.5 m/s2
hope this helps.
 
2 years ago
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