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Find average acceleration over 10 seconds.. ........... Graph is shown in attachment

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2 years ago

Susmita
425 Points
```							For 0 to 5 s,it is a straight line passing through origin with slope 10/5=2.The equation of straight line is a=2t.Or,dv/dt=2tOr,dv=2tdtIntegrate dv from 0 to v and dt from t 0 to 5,you will getv=25.For the next 5s,initial velocity u=5m/s and acceleration a=10m/s2.So final velocityv=u+at=25+10×5=75 m/sSo average acceleration in 10 s is(75-0)/10=7.5 m/s2hope this helps.
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2 years ago
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Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions