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```
find an equation of the tangent line to the curve y= e ^x / 1+x^2 at the point(1, e/2)

```
2 years ago

Ravneet
104 Points
```							step 1 ; find dy/dx . you can apply the quotient rule                     RESULT ;  ex(1-x)2/(1+x2)2step 2; as we have to find equation of the tangent at a particular point, so just put that point in dy/dx                     RESULT ; dy/dx = 0step 3 : use point-slope form of straight line wher m = 0                       so answer  y = 1/e
```
2 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions