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`        F=20N,m1=m2=3and acceleration is 0.5m/s^2.Friction forces on the two blocks are eaqual what is magnitude`
10 months ago

Arun
22572 Points
```							First consider the 2 masses as a single object. Total mass = 3+3=6 kg Resultant force, F= ma = 6 x 0.5 = 3N Since an external force of 20N is being applied, the frictional force must be 20-3=17N (8.5N on each mass). Now consider m1 by itself. The resultant force on it = ma = 3 x 0.5=1.5N Let T = tension in rope joining m1 and m2 The only 2 horizontal forces on m1 are T (to right) and 8.5N (friction to the left) Resultant horizontal force on m1 = T1 - 8.5 T-8.5 = 1.5 T = 10N
```
10 months ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions