badge image

Enroll For Free Now & Improve Your Performance.

×
User Icon
User Icon
User Icon
User Icon
User Icon

Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11

                        

Explain how conservation of momentum applies to a handball bouncing off a wall.

5 years ago

Answers : (3)

Kevin Nash
askIITians Faculty
332 Points
							Law of conservation of linear momentum states that, in an isolated system (no external force), the algebraic sum of momenta of bodies, along any straight line, remains constant and is not changed due to their mutual action and reaction on each other.
The momentum of particle (p) is equal to the mass of particle (m) times the velocity of particle (v).
So, p = mv …… (1)
Let us consider m is the mass of the ball and v is the velocity of the ball when the ball is collides with wall.
So using equation (1), the momentum of the ball before collision (p1) will be,
p1= mv …… (2)
After collision, when the ball re bounces, the velocity of the ball will be, -v.
So again using equation (1), the momentum of the ball after collision (p2) will be,
p2= -mv …… (3)
Conservation of linear momentum states that, the algebraic sum of momenta of bodies, along any straight line, remains constant and is not changed due to their mutual action and reaction on each other.
p1 + p2 = 0
So, mv + (-mv) = 0 …… (4)
From equation (4) we observed that, linear momentum of the hand ball is conserved.
5 years ago
Rizwan Mahsood
41 Points
							The rebouncing of a handball from the wall is a type of elastic collision in which both momentum and kinetic energy remains constant.For conservation of momentum isolated system must be required.We know the conservation expression for a single particle,P=mv (before collision)P=-mv (after collision)The negative sign is because of velocity is a vector quantity and it is opposite to the initial velocity vector.Thus the net momentum becomes,Pnet=(mv)+(-mv)=0
						
3 years ago
Rizwan Mahsood
41 Points
							And also we can write this expression asP=mv(before collision) -mv(after collision)If P=0 (conservation of momentum)Then we can write,mv(before collision)-mv(after collision)=0Or,mv(before collision)=mv(after collision)Hence it means momentum is conserved
						
3 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details