 ×     #### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```
Explain how conservation of momentum applies to a handball bouncing off a wall.

```
5 years ago

```							Law of conservation of linear momentum states that, in an isolated system (no external force), the algebraic sum of momenta of bodies, along any straight line, remains constant and is not changed due to their mutual action and reaction on each other.The momentum of particle (p) is equal to the mass of particle (m) times the velocity of particle (v). So, p = mv …… (1)Let us consider m is the mass of the ball and v is the velocity of the ball when the ball is collides with wall.So using equation (1), the momentum of the ball before collision (p1) will be,p1= mv …… (2)After collision, when the ball re bounces, the velocity of the ball will be, -v.So again using equation (1), the momentum of the ball after collision (p2) will be,p2= -mv …… (3)Conservation of linear momentum states that, the algebraic sum of momenta of bodies, along any straight line, remains constant and is not changed due to their mutual action and reaction on each other.p1 + p2 = 0So, mv + (-mv) = 0 …… (4)From equation (4) we observed that, linear momentum of the hand ball is conserved.
```
5 years ago
```							The rebouncing of a handball from the wall is a type of elastic collision in which both momentum and kinetic energy remains constant.For conservation of momentum isolated system must be required.We know the conservation expression for a single particle,P=mv (before collision)P=-mv (after collision)The negative sign is because of velocity is a vector quantity and it is opposite to the initial velocity vector.Thus the net momentum becomes,Pnet=(mv)+(-mv)=0
```
3 years ago
```							And also we can write this expression asP=mv(before collision) -mv(after collision)If P=0 (conservation of momentum)Then we can write,mv(before collision)-mv(after collision)=0Or,mv(before collision)=mv(after collision)Hence it means momentum is conserved
```
3 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Mechanics

View all Questions »  ### Course Features

• 101 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution  ### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions