Navjyot Kalra
Last Activity: 9 Years ago
We have to find out the minimum force (F) that the field must exert on the electron being removed.
To obtain the minimum force (F), substitute 4.5 eV for W and 3.4 nm for s in the equation F = W/s,
F = W/s
= (4.5 eV/3.4 nm)
= (4.5 eV/3.4 nm) (1.6×10-19 J/1 eV) (1 nm/10-9 m)
= 2.1×10 -10 J/m
= 2.1×10 -10 N …… (3)
From equation (3) we observed that, the minimum force (F) that the field must exert on the electron being removed would be 2.1×10 -10 N.