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Electric fields can be used to pull electrons out of metals. To remove an electron from tungsten, the electric field must do 4.5 eV of work. Suppose that the distance over which the electric field acts is 3.4 nm. Calculate the minimum force that the field must exert on the electron being removed.
Electric fields can be used to pull electrons out of metals. To remove an electron from tungsten, the electric field must do 4.5 eV of work. Suppose that the distance over which the electric field acts is 3.4 nm. Calculate the minimum force that the field must exert on the electron being removed.

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5 years ago

Navjyot Kalra
654 Points
```							We have to find out the minimum force (F) that the field must exert on the electron being removed.To obtain the minimum force (F), substitute 4.5 eV for W and 3.4 nm for s in the equation F = W/s,F = W/s = (4.5 eV/3.4 nm) = (4.5 eV/3.4 nm) (1.6×10-19 J/1 eV) (1 nm/10-9 m) = 2.1×10 -10 J/m= 2.1×10 -10 N …… (3)From equation (3) we observed that, the minimum force (F) that the field must exert on the electron being removed would be 2.1×10 -10 N.
```
5 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions