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# Displacement y of particle is given by y=2t+t2-2t2.the velocity of the particle when acceleration is zero

Vikas TU
14149 Points
5 years ago
velocity of the ;particle is the differential of the displacent of y.
.i.e. dy/dt = 2 + 2t – 6t^2
acceleration is the differentiation of velocity or double differentale of displacement.
.i.e. a = 2 – 12t = 0
t = 1/6
velocity at t = 1/6 now u can calcclate by putting t in velocity eqn.

Note: that last term is 2t^3 i think not t^2.
Anuj Rampuriya
13 Points
one month ago
velocity of the particle is the differential of y

now,
dy/dt=2t-6t^2
dy/dt={2-12t}-eq 1

0=2-12t
12t=2
t=2/12
t=1/6
putting value of t in the given eq
when acceleration is zero
v=2+2/6-6(1/6)2
=2+1/3-1/6
=13/6