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Grade: 12th pass
        
Determine the horizontal force P to be applied to a block of weight of 1800N to hold it in position on a smooth inclined plane, which makes an angle 300 with horizontal reference line.
 
 
3 months ago

Answers : (2)

Vikas TU
9517 Points
							
Dear student 
Weight downward = 1800N 
Horizontal force required to keep Block in inclined plane = mgSin30 
mg = 1800N 
Horizontal force = 1800*1/2 
=> 900 N 
Hope this helps 
3 months ago
Joel Sudhakar
23 Points
							
dear brother 
here weight acting downward =1800N
the force acting  along the plane to hold the block is =mgSin30=1800*1/2=900
but here we need to calculate the horizontal force ‘P’which is acting on the body 
so, we resolve the horizontal force ‘P’ into x-component and y-component as PCos30 and Psin30 respectively
then Pcos30=mgSin30
P=(1800*1/2)/Cos30=1039.23N
 
3 months ago
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