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Determine horizontal velocity with which a stone must be projected horizontally from a point P, so that it may hit the inclined plane perpendicularly. the inclination of the plane is 'theta' and point P is at height 'h' above the foot of the incline
let y be the distance when it hots the inclined plane. The height abob=ve plane would be = h – ythenin horizontal direcn.vx = vand in vertical direcn.vy = root2 * g * yfrom the geometry of inclined plane,tanthetha = vx/vy = v/root(2)*g*yorv = root2*g**tan(thetha).
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