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Grade: 11
        
Derive the expression for moment of inertia of a rod about it's centre and perpendicular to the rod
6 months ago

Answers : (1)

k sibin
37 Points
							
lets take a dm mass x distance from its centre on the rod of mass m and length l
I=∫l/2-l/2 (m/l).dx)x2
 
 =m/l[x3/3]-l/2l/2 
=m/l[l3/24 + l3/24]
=ml/12
6 months ago
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