Grade 11Mechanics
Derive the expression for moment of inertia of a rod about it's centre and perpendicular to the rod
Derive the expression for moment of inertia of a rod about it's centre and perpendicular to the rod
1 Answer
k sibin
lets take a dm mass x distance from its centre on the rod of mass m and length l
I=∫l/2-l/2 (m/l).dx)x2
=m/l[x3/3]-l/2l/2
=m/l[l3/24 + l3/24]
=ml2 /12
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