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`        Derive the equation -v =u+at by graphical method .A stone dropped from a height reaches the ground in 2sec .calculate its speed  just before it hits the ground`
2 years ago

Arun
23330 Points
```							Dear Vikram Initial speed (u) = 0  (as the stone is at rest)Time = 2 secondsAcceleration = 9.8m/s²i) According to first equation of motion:v = u + atv = 0 + 9.8 x 2v = 19.6 m/sThis is the speed just before stone hits the ground  RegardsArun (askIITians forum expert)
```
2 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions