MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11
        Consider a small surface area of 1 mm2 at the top of a mercury drop of radius 4.0 mm. Find the force exerted on this area (a)  by the air above it (b) by the mercury below it and (c) by the mercury surface in contact with tension of mercury it. Atmospheric pressure = 1.0 × 105 Pa and surface tension of mercury = 0.465 N m-1. Neglect the effect of gravity. Assume all numbers to be exact. 
5 years ago

Answers : (1)

Kevin Nash
askIITians Faculty
332 Points
							Sol. a) F = P0A
b) Pressure = p0 + (2T/r)
F = P’A = (P0 + (2T/r)A
c) P = 2T/r
F = PA = 2T/r A

						
5 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details