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consider a particle initially moving with 5 m s -1 starts decelerating at a constant rate of 2 m s -2 . find the distance travelled in the third second.
velocity after 2 sec = 5 – 2*2 = 1m/sso distance covered in next 1/2 sec = 1*1 – ½*2*(1/2)2 = ¾ mnow its velocity become zero and reverse the directionthen distance in next ½ sec = ½*2*(1/2)2 = ¼ MSO distance in 3rd sec = ¾ + ¼ = 1m.
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