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Consider a one-dimensional collision that involves a body of mass m1 originally moving in the positive x direction with speed v0 colliding with a second body of mass m2 originally at rest. The collision could be completely inelastic, with the two bodies sticking together, completely elastic, or somewhere in between. After the collision, m1 moves with velocity v1 while m2 moves with velocity v2 (a) If m1 > m2, then (A) -v0 (B) 0 (C) 0 (D) v0 (b) and (A) -v0 (B) 0 (C) v/ 2 (D) v0 (c) If m1 (A) -v0 (B) -Vo (C) 0 (D) 0 (d) and (A) -v0 (B) -v0 (C) 0 (D) 0

```
8 months ago

Parth
58 Points
```							See in this case let assume of coefficient of restitution (COR)= e ; -e = (v2-v1)/(u2-u1)you ‘ve to conserve momentum and energy to find v1,v2, then you ‘ve to compare it with v0 which become very handyso if this question is a single correct then assume collision to be perfectly inelastic;then you’ll find v1 = v2 =m1* v0/(m1+m2)then for 1 – options2 – option B3- option B4 -option Ccoz in option 3 and 4 using the equation of C.O.R ; and conserving momentum you’ll find for m2>m1v1 can  be negative; v2 can never be negativehope it helpspls approve
```
8 months ago
Vikas TU
14146 Points
```							Dear sttudent Please refer the link https://www.askiitians.com/forums/Mechanics/consider-a-one-dimensional-collision-that-involves_260657.htm
```
8 months ago
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• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions