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Let ‘m’ be the mass of the vehicle. So, frictional force experienced by the vehicle on its tyres is, f = µmg
So, the acceleration of the vehicle due to this frictional force is, a = -µg (acceleration is directed opposite to the motion of the vehicle)
Now using,
v2 = u2 + 2as
=> 0 = v2 - 2 µgs
[initial velocity = v, final velocity = 0]
So, s = v2/(2µg)
v = 72 *5/18 = 20 m/sec
Hence
S = 400 /2 * 0.5 *10 = 40 m
Regards
Arun (askIITians forum expert)
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