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`        Compute your average velocity in the following two cases: (a) You walk 73.2 m at a speed of 1.22 m/s and then run 73.2 m at a speed of 3.05 m/s along a straight track. (b) You walk for 1.00 min at a speed of 1.22 m/s and then run for 1.00 min at 3.05 m/s along a straight track. (c) Graph x versus t for both cases and indicate how the average velocity is found on the graph.Please help me with the graph`
one year ago

```							Well keep in mind that distance= rate*time so time=distance/rate and rate= distance/time. Also Average velocity= distance total moved divided by time that passed (time it took to move that distance) With this information we can begin a) 1.22m/s=r 73.2m=d t=? we can solve with t=d/r and get t =73.2/1.22 and we get t=60sec. Doing the same for 3.05 = r 73.2 = d t =? t = 73.2m/3.05m/s= 24secs. Using the average velocity information we know we went 73.2m+73.2m in distance 60 seconds+24 seconds in time so 146.4m/84secs.= 1.74m/s b) We need to find distance now using the previous formulas we can solve d = r*t d = 1.22m/s*60sec d = 73.2m and for the other d=3.05m/s*60s d=183m so same situation with average velocity 256.2m/120secs= 2.135 m/s
```
one year ago
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