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Grade 11Mechanics

Coefficient of friction between 5kg and 10kg is 0.5 , if friction between them is 20N. What is the value of force applied on 5kg.the floor is frictionless

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Profile image of Arya Kapoor
9 Years agoGrade 11
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2 Answers

Profile image of Vikas TU
8 Years ago
Dear Student,
The internal force acting is 0.
hence both the bodies can be considered as one body of mass 15kg
moving with acceleration a.

Doing FBD of 10kg block
pseudo force=frictional force
=>10a=20
=>a=2m/s

FBD of 5kg block, and solving the equation,
F-20=15a
=>F=30+20 = 50N
Cheers!!
Regards,
Vikas (B. Tech. 4th year
Thapar University)
Profile image of Saurav
7 Years ago
Vikas's concept is right, yes the acceleration of both blocks would be 2m/s^2. But you made mistake in 2nd part.
 
FBD of 2nd block
F-20=5a
F=20+10N
F=30N not 50N