Certain neutron stars (extremely dense stars) are believed to be rotating at about 1 rev/s. if such a star has a radius of 20 km (a typical value), (a) what is the speed of a point on the equator of the star, and (b) what is the centripetal acceleration of this point?

Question

Deepak Patra · Answer

Therefore, the speed with which the point at equator of a Neutron star rotates is 1.26 x 10 5 . Therefore, the acceleration of the point on equator of Neutron star is 7.89 x 10 5 m /s 2 . .

Shubham Singh · Answer

(​a) speed = 40pi km/s (b) acceleration = 80(pi) 2 km/s

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Certain neutron stars (extremely dense stars) are believed to be rotating at about 1 rev/s. if such a star has a radius of 20 km (a typical value), (a) what is the speed of a point on the equator of the star, and (b) what is the centripetal acceleration of this point?

Certain neutron stars (extremely dense stars) are believed to be rotating at about 1 rev/s. if such a star has a radius of 20 km (a typical value), (a) what is the speed of a point on the equator of the star, and (b) what is the centripetal acceleration of this point?

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Certain neutron stars (extremely dense stars) are believed to be rotating at about 1 rev/s. if such a star has a radius of 20 km (a typical value), (a) what is the speed of a point on the equator of the star, and (b) what is the centripetal acceleration of this point?

Certain neutron stars (extremely dense stars) are believed to be rotating at about 1 rev/s. if such a star has a radius of 20 km (a typical value), (a) what is the speed of a point on the equator of the star, and (b) what is the centripetal acceleration of this point?

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