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Can you please provide solution of this kinematics question with full process.
Can you please provide solution of this kinematics question with full process.

```
2 years ago

Khimraj
3007 Points
```							speed of car = 90*5/18 = 25 m/saccleration of of motor cycle = 5m/s2distance between themd = 25*t – ½*5*(t-2)2for max ddd/dt = 0dd/dt = 25 – 5*(t-2) = 0t = 7 secat t= 7 d = 112.5mHope it clears. If you like answer thenplease approve it.
```
2 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions