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Grade: 

                        
Can you please provide solution of this kinematics question with full process.
2 years ago

Answers : (1)

Khimraj
3007 Points 
							
speed of car = 90*5/18 = 25 m/s
accleration of of motor cycle = 5m/s2
distance between them
d = 25*t – ½*5*(t-2)2
for max d
dd/dt = 0
dd/dt = 25 – 5*(t-2) = 0
t = 7 sec
at t= 7 
d = 112.5m
Hope it clears. If you like answer thenplease approve it.
2 years ago
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