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2 years ago

Eshan
2095 Points
							Dear student,At the time it strikes the point C, the displacement in vertical direction$\dpi{80} usin\theta t-\dfrac{1}{2}gt^2=y$and the displacement in horizontal direction=$\dpi{80} (ucos\theta )t=\dfrac{10}{3}+ycot{37^{\circ}}$Solving the two equations to eliminate ‘t’ will give the answer.Maximum height attained by the particle=$\dpi{80} \dfrac{u^2sin^2\theta}{2g}$

2 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions