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Grade:

                        

Can anyone please answer the 9th question ......in the attached image

2 years ago

Answers : (1)

Eshan
askIITians Faculty
2095 Points
							Dear student,

At the time it strikes the point C, the displacement in vertical direction

usin\theta t-\dfrac{1}{2}gt^2=y

and the displacement in horizontal direction=(ucos\theta )t=\dfrac{10}{3}+ycot{37^{\circ}}

Solving the two equations to eliminate ‘t’ will give the answer.

Maximum height attained by the particle=\dfrac{u^2sin^2\theta}{2g}
2 years ago
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