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`        Calculate the % contraction of a rod moving with velocity of 0.8c in a direction inclined at 60° of its length.`
one year ago

Khimraj
3008 Points
```							 Let lo be the length of the rod in the frame in which it is at rest and s' is the frame which is moving with a speed 0.8c in a direction making an angle 60° with x-axis. The components of lo along and perpendicular to the direction of motion are lo cos 60° and lo sin 60° respectively.Now length of the rod along the direction of motion = lo cos 60°_/1-(0.8) 2/c2= lo/2×0.6= 0.3 lo.Length of the rod perpendicular to the direction of motion.= lo sin 60°=_/3/2 loLength of moving rodl = [(0.3lo)2+{lo_/3/2} 2] 1/2= 0.916 lo.Percentage contraction= lo-0.916lo/lo×100= 8.4%.
```
one year ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions