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block b moves to the right with a constant velocity v. velocity of block b is (assume all pulleys and strings are ideal)

shad , 5 Years ago
Grade 9
anser 1 Answers
Arun

Last Activity: 5 Years ago

Let xE= length of bottom rope length, XD= middle  rope length, Xc=top rope length, X is fixed at bottom rope starting point, XA= Distance upto block A (POSITIVE TO THE left) , XB= distance upto mass B (positive to the right).
so  LE=XB  
 
LD=XB+XA       (1)
 
LC=XB+XA   (2)
 
L=LE+LD+LC = 3XB+2XA   (3)
 
L= CONSTANT ,
 
diff (3) → 0 =3VB+2VA→ VA = -3VB/2
 
VAB=VB-(-VA)  (note the comment above for VA is negative)
 
VAB = VB-(-(-3VB/2))
VAB =(1-3/2) VB = -0.5 VB
VAB =-0.5 V0
 
For velocity, right is taken as positive. Since answer is negative the block moves towards left.
 
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