Freed body diagram of B:
F will be left
T will be on right
N2 will be on top of block acting downward
f2 will be on top of block acting rightwards
f1 will be on bottom of block acting rightwards
mBg will be acting downwards from CG of block
N1 will be acting upwards at bottom of block
F = T+f1+f2
N1 = N2+mBg
f1 = mu*N1 ,f2 = mu*N2 ,
F = T+mu(N1+N2)
F = T+mu(N2+mBg+N2) = T+mu(2N2+mBg)
Given that mBg = 4N, mu = 0.3
F = T+0.3(2N2+4)
Fred body diagram of A
T will be on right
N2 will be acting upwards at bottom of block
f2 will be at bottom of block acting leftwards
mAg will be acting downwards from CG of block
T = f2 = muN2 = mu(mAg) = 0.3 * 2N = 0.6N
F = 0.6 + 0.3(2*0.6+4) = 2.16 N