Ball A is thrown vertically up from the ground at time t=0 with an initial velocity of 55m/sec. Ball B is thrown vertically up from ground at t=4 with an initial velocity of 55m/sec. Calculate the maximum distance between the two balls and the time (t) at which this occurs.

There will be maximum distance when one ball is at ground and other at the highest point .So t= (d ) relative / (v)relative4 = d / 110 { relative speed will be 55+55=110} Both are in opposite directiond= 440mIf you find it useful please approve it.