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`        At what altitude in meter will the acceleration Due to gravity be 20% of that the earth`s surface (radius of Earth is R)`
2 years ago

```							Acceleration due to gravity is represented as g.The value of g on the surface of earth is 9.8ms−2The formula for g is g=GMR2Where G is the universal gravitational constant. Its value = 6.67408×10−11m3kg−1s−2 .M is the mass of earth.R is the radius of earth.As we see can from the formula, that g∝1R2 -------(1)Lets take acceleration due to gravity at a height H from the surface as g'g'∝1(R+H)2------(2)Lets divide equation 2 with equation 1, to get the relation between g' and gg'g=R2(R+H)2⇒g'=g(1+HR)2Now that we have derived a relation between g'and g, lets solve your question by putting H=2Rin the above equation.We get g'=g9⇒ acceleration due to gravity at height 2R form the surface of earth is 19th of gNote:The above formula is only valid for H>R.For HR, the relation between is g' and g isg'=g(1−HR)If the derivation is required, then feel free to ask, and I will add it.
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2 years ago
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