#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-5470-145

+91 7353221155

CART 0

• 0
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

# At time =0s the particle starts moving alopng x – axis. If its kinetic energy uniformly with time T , the net force acting on it must be prorportional to  T^1/2 constant T 1/squareroot T

Nirmal Singh.
7 years ago
The Right question is this – – – -At time =0s the particle starts moving alopng x – axis. If its kinetic energy uniformly with time T , the net force acting on it must be prorportional to-----------

As per question we know that the K.E increase with time T

So K,E = k*T

0.5 m v2= k T

so v = sqrt (2k T / m)

a = dv / dt = ½ sqrt (2k.mT)

So Force F = ma

F = m *½ sqrt (2k.mT)

Hence Force is prportaional to the1/squareroot T

Regards,

Nirmal SIngh